Calculate S for 1 mol of Hg vapor at 298.15 K if its pressure at that temperatur

Question

Calculate S for 1 mol of Hg vapor at 298.15 K if its pressure at that temperature is 0.001960 torr. Given a mol of^12C(g) and^13C(g), determine the ratio of the partition functions at the same volume and temperature. Without calculating an actual number, can you determine which one will have a larger value of q? According to the Sackur-Tetrode equation, is S proportional or inversely proportional to these state variables? temperature pressure. Do your answers agree with phenomenological thermodynamics' predictions on the variation of 5 with these variables? Use equation 17.56 to determine the change in energy, Delta E, when 1 mole of Ar is heated from 298 K to 348 K at constant volume. Compare this result with the change in energy calculated using (mass)(specific heat)(change in temperature). The specific heat of argon is 20.79 J/(mol middot K).

Explanation / Answer

Here I wish S is specific gravity

Assume that Hg follows ideal gas law,

Pressure = 0.001960 torr x 760 = 1.4896 atm x 1.01 x 105 == 1.50 x 105 Pa

density = PM/RT

= 1.50 x 105 Pa x 200 kg/mol / ( 8.314 x 298.15 )

= 12138.8 kg/m3

Specific gravity = 12138.8 kg/m3 / 1000  kg/m3

  = 12.138

=

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.