Calculate moles of \"unknown\" solution 50 mL of a 1.067 M solution of HCI was d

Question

Calculate moles of "unknown" solution 50 mL of a 1.067 M solution of HCI was diluted to 250 mL. The diluted HCI solution was then titrated with an unknown concentration of KOH. It is found that an average volume of 24.20 mL of KOH is required to reach an endpoint in a titration with 25.00 mL of the dilute acid solution. The equation for the reaction is; H^+_(aq) + OH_(aq) rightarrow H_2 O_(l) Calculate the moles of your unknown solution (KOH). Remember to use the correct number of significant figures.

Explanation / Answer

According to given reaction between HCl and KOH, one mole of HCl reacts with one mole of KOH. Therefore, Number of moles of KOH will be same as the number of moles of HCl.

Number of moles of HCl in given stock solution can be calculated as follows:

Number of moles of HCl = Volume of solution in L x Molarity (mol/L)

Number of moles of HCl = 50mL x (1L/1000mL) x 1.067M

Number of moles of HCl = 0.053 moles

Since, stock solution containing 0.053 moles of HCl is diluted to 250mL and 25mL of it is used in titration. Therefore, number of moles in 25 mL of diluted HCl solution can be calculated as follows:

Number of moles of HCl in 25mL diluted solution = (0.053mol / 250mL) x 25mL

Number of moles of HCl in 25mL diluted solution = 0.0053 moles

Since, number of moles of KOH is same as that of HCl.

Therefore, number of moles of KOH is 0.0053moles

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