Each particl does the nuclide symbol beta^+ represent positron helium nucleus el
ID: 998892 • Letter: E
Question
Each particl does the nuclide symbol beta^+ represent positron helium nucleus electron proton gamma photon Which of the following nuclides will produce^233 Pa upon undergoing alpha decay?^234 Pa^233 U^229 Ra^237 NP^237 Np^233 Th Which of the following statements about^248 Bk is incorrect? If^248 Bk were to undergo spontaneous fission, the products would be^247 Bk and a neutron. If^248 Bk were to undergo beta decay, the products would be^248 Cf and a beta particle. If^248 Bk were to undergo alpha decay, the products would be^244 Arn and an alpha particle. If^248 Bk were to undergo electron capture, the only product would be^248 Cm. If a metastable form of^248 Bk were to undergo gamma decay, the products would be^248 Bk and a gamma ray. can be prepared by electron capture from which of the following?^56 Mn^55 Fe^55 Cr^51 V^57 coExplanation / Answer
1) + nuclide symbol represent positron. Option-A
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2) On -Decay mass number decreases by 4 units in daughter element.
Other way round we can say that parent nuclide is with mass number more by 4 unit than daughter nuclide formed by emission 1- particle.
Hence 233Pa would have been formed from 233+4Np = 237Np nuclide.
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3)
A. INCORRCT. On spontaneous fission products would not be just 247Bk and a neutron.
Fission results in formation of two nuclides with small mass number.
B. Correct. 24897Bk were undergo decay and forms 24898Cf (as on emission mass number remains same but atomic number increases by 1) and hence,
24897Bk ---------> 24898Cf + 0–1
C. Correct. On 1- particle decay Mass number decrease by 4 and atomic number by 2 units.
24897Bk ---------> 24495Am + 42
D. Correct by K-capture Proton get converted into neutron and hence mass number which is the sum of proton and neutron number remains same but as proton number decreased by 1 atomic number decreases by 1.
24897Bk + 0–1e---------> 24896Cm
E. Correct. By gamma ray decay metastable species losses excess energy and become stable and no change in mass and atomic number takes place.
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4) Cannot see the nuclide to be prepared by K capture.
K capture phenomenon explained above.
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