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A voltaic cell is constructed from a standard I 2 | I - half cell (E° red = 0.53

ID: 1006337 • Letter: A

Question

A voltaic cell is constructed from a standard I2|I- half cell (E°red = 0.535V) and a standard Pb2+|Pb half cell (E°red = -0.126V).

The anode reaction is:



The cathode reaction is:



The spontaneous cell reaction is:



The cell voltage is  V.

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A voltaic cell is constructed from a standard Cu2+|Cu half cell (E°red = 0.337V) and a standard Br2|Br- half cell (E°red = 1.080V).

The anode reaction is:



The cathode reaction is:



The spontaneous cell reaction is:



The cell voltage is  V.

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A voltaic cell is constructed from a standard Cu2+|Cu+ half cell (E°red = 0.153V) and a standard Hg2+|Hg half cell (E°red = 0.855V).

The anode reaction is:



The cathode reaction is:



The spontaneous cell reaction is:



The cell voltage is  V.

(aq)(s)(l)(g) + (aq)(s)(l)(g)    (aq)(s)(l)(g) + (aq)(s)(l)(g)

Explanation / Answer

AnodePb+2 +2e- ------>Pb Eo=-0.13V ( Oxidation)

reversing it    Pb--------> Pb+2 +2e- Eo= 0.13V (1)

2e- + I2 --> 2I- Cathode ( reduction ) Eo= 0.54V (2)

Addition of the above reactions give Pb+ 2I- -------> Pb+2 +I2 Eo= 0.54+0.13= 0.67V

2. Cu+2 +2e-------->Cu    Anode reaction Eo= 0.337

reversiing it gives Cu ----> Cu+2 +2e- Eo= -0.337 V

2Br- +2e--------> Br2 cathode Eo= 1.07

addition gives Cu +2Br- ------> Cu+2 + Br2 Eo= -0.34+1.07=0.73V

3.

Cu ------> Cu+2 +2e-    Anode reaction ( oxidation) Eo= -0.34V

Hg+2 +2e- -----Hg Eo= 0.85V and addition gives Cu+ Hg+2---------> Cu+2 + Hg Eo= 0.85-0.34= 0.51V

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