A balloon filled with 0.705 mol of gas contracts reversibly from 1.5 L to 0.25 L

Question

A balloon filled with 0.705 mol of gas contracts reversibly from 1.5 L to 0.25 L at a constant temperature of 10.0 degree C. It simultaneously loses 570 J of heat. Calculate q, w, Delta U, Delta H for the process. a) A system containing 5.0 mol of an ideal gas for which C_v, m = 35.17 j/(mol K). Curved path corresponds to PV = nRT where T_1 = T_3. Calculate q, w, Delta H and Delta H for each segment and for the cycle, b) Calculate q, Delta H and Delta H for the reverse of each segment and for the reverse cycle.

Explanation / Answer

dW = -PdV

= -nRT ln(V2/V1)

= - 0.705 mol x 8.314 J/mol K x 283.15 K x Ln(0.25/1.5)

=2974 J

dU =dQ+dW

= -570 J +2974 J

dU =2408 J

According to chegg guidelines, only one question should be answered

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