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Calculate the amount of each reagent required to make 500ml of media: -0.5% year

ID: 1031581 • Letter: C

Question

Calculate the amount of each reagent required to make 500ml of media: -0.5% years extract -2% tryptone -10mM NaCl (from 5M stock) -2.5mM KCl (from 2.5M stock) -10mM MgCl2 (1M stock) -10mM MgSO4 (powder) -20mM glucose (from 50% solution) Calculate the amount of each reagent required to make 500ml of media: -0.5% years extract -2% tryptone -10mM NaCl (from 5M stock) -2.5mM KCl (from 2.5M stock) -10mM MgCl2 (1M stock) -10mM MgSO4 (powder) -20mM glucose (from 50% solution) -0.5% years extract -2% tryptone -10mM NaCl (from 5M stock) -2.5mM KCl (from 2.5M stock) -10mM MgCl2 (1M stock) -10mM MgSO4 (powder) -20mM glucose (from 50% solution)

Explanation / Answer

0.5% years extract

= 0.5*500/100 = 2.5g

2% tryptone

=2*500/100 = 10g

10mM NaCl (from 5M stock)

M1V1=M2V2

5M*V1=0.010M*500mL

V1=1mL

2.5mM KCl (from 2.5M stock)

M1V1=M2V2

2.5M*V1=0.0025M*500mL

V1=0.5mL

10mM MgCl2 (1M stock)

M1V1=M2V2

1M*V1=0.010M*500mL

V1=5mL

10mM MgSO4 (powder)

10*10-3 M= moles / 0.5 L

moles = 5*10-3 mol

weight = moles * molar mass = 5*10-3 * 120.366 = 0.6g

20mM glucose (from 50% solution)

50% glucose solution is 50g/100ml or 500g/litre

1 mole of glucose = 180 g/mol

500/180 moles / liters = 2.78M glucose

M1V1=M2V2

2.78M*V1=0.020M*500mL

V1=3.6mL

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