What is the precent ionization of ammonia at this concentration? Given: Kb= 1.8

Question

What is the precent ionization of ammonia at this concentration?

Given: Kb= 1.8 X 10^-5, pH = 11.02

asteringChemistry: Chapter 16 - Microsoft Edge session.masteringchemistry.com/myct/itemView?assignmentProblemID-100720969 Chapter 16 H and Percent lonization of a Weak Base 7 of 10 Constants Periodic Table Part A Ammonia, NHs, is a weak base with a Kb value of 1.8 x 105 What is the pH of a 6.00x102 M ammonia solution? Express your answer numerically to two decimal places. View AvailableHint(s) pH11.02 Previous Answers Correct Part B What is the percent ionization of ammonia at this concentration? Express the percentage numerically to three significant figures. View Available Hintfs) % ionization-

Explanation / Answer

pH = 11.02

pOH = 14 - 11.02 = 2.98

- Log[OH-] = 2.98

[OH-] = 10-2.98

[OH-] = 0.00105 M

NH3 (aq.) + H2O (l) = NH4+ (aq.) + OH- (aq.)

% dissocaition of NH3 = molarity of NH3 ionised * 100 / initial molarity = 0.00105 * 100 / 0.0600 = 1.75 %

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.