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iPad?e. ??3:45 cvg.cengagenow.com ???? Bing Google Yahoo ???? ?+ Write The Cell ????·??? ???????… Cengage Brain-- O owLV2 l Onli. ???? REVIEW SPRING BREAK Question 1 Question 2 Cream of tartar, a common ingredient in cooking, is the common name for potassium bitartrate (abbreviated KBT, molar mass 188.2 g/mol). Historically, KBT was a crystalline solid that formed on the casks of wine barrels during the fermentation process. Calculate the maximum mass of KBT that can dissolve in 260.0 mL of solution to make a saturated solution. The Ksp value for KBT is 3.8 x 10 1 pt 1 pt Question 3 1 pt 1 pt 1 pr 1 pt Question 4 Mass- Question Question6 Question 7 Submit Answer Try Another Versiorn 10 item attempts remaining Question 8 Question 9 Question 10 Question 11 1 pt 1 pt 1 pt 1 pt 1 pt Question Question 13 Question 14 Question 15 Question 16 1 pt Progress: 0/16 items Due Apr 8 at 11:55 PM Previous Next Finish Assignment Email Instructor Save and Exit Cengage Learning |I Cengage Technical Support

Explanation / Answer

In 260.0 mL 0.9537 g of potassium bitartrate can dissolve.

Ksp of KBT = 3.8 x 10-4 for potassium bitartrate, KC4H5O6

Ksp= [K+][C4H5O6-] = 3.8 x 10-4

Molar solubility = ?3.8 x 10-4 = 0.01949 mol / L

M.W = 188.2 g/mol

Mass of KC4H5O6 that can dissolve in 1 L of water = 188.2 g/mol x 0.01949 mol / L = 3.668 g /L

So the amount of KC4H5O6 that can dissolve in 260.0 mL = 3.668 g /L x 260/1000 = 0.9537 g.

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