Calculate the change in Gibbs free energy for each of the following sets of ? H
ID: 1046453 • Letter: C
Question
Calculate the change in Gibbs free energy for each of the following sets of ?Hrxn, ?Srxn, and T.
Part A
?H?rxn= 86 kJ , ?Srxn= 147 J/K , T= 300 K
Express your answer using two significant figures.
Predict whether or not the reaction in part A will be spontaneous at the temperature indicated.
Part B
?H?rxn= 86 kJ , ?Srxn= 147 J/K , T= 757 K
Express your answer using two significant figures.
Predict whether or not the reaction in part B will be spontaneous at the temperature indicated.
Part C
?H?rxn= 86 kJ , ?Srxn=? 147 J/K , T= 300 K
Express your answer using two significant figures.
Predict whether or not the reaction in part C will be spontaneous at the temperature indicated.
Part D
?H?rxn=? 86 kJ , ?Srxn= 147 J/K , T= 393 K
Express your answer using two significant figures.
Predict whether or not the reaction in part D will be spontaneous at the temperature indicated.
Explanation / Answer
A)
?Ho = 86.0 KJ
?So = 147 J/K
= 0.147 KJ/K
T = 300 K
use:
?Go = ?Ho - T*?So
?Go = 86.0 - 300.0 * 0.147
?Go = 41.9 KJ
Answer: 42 KJ
B)
?Ho = 86.0 KJ
?So = 147 J/K
= 0.147 KJ/K
T = 757 K
use:
?Go = ?Ho - T*?So
?Go = 86.0 - 757.0 * 0.147
?Go = -25.279 KJ
Answer: -25 KJ
C)
?Ho = 86.0 KJ
?So = -147 J/K
= -0.147 KJ/K
T = 300 K
use:
?Go = ?Ho - T*?So
?Go = 86.0 - 300.0 * -0.147
?Go = 130.1 KJ
Answer: 130 KJ
D)
?Ho = -86.0 KJ
?So = 147 J/K
= 0.147 KJ/K
T = 393 K
use:
?Go = ?Ho - T*?So
?Go = -86.0 - 393 * 0.147
?Go = -143.771 KJ
Answer: -1.44*10^2 KJ/mol
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