Can you calculate the relative range for the unknown and standardization Trial 1

Question

Can you calculate the relative range for the unknown and standardization

Trial 1 Trial 2 Trial 3 STANDARDIZATION weight of As20. (tpurity- Valume of KMno corrected %) cted for purityLD Do 10D 400 Relative Range (ppt) UNKNON IRON OXIDE Weight of Iron oxide.... 20020 Volume of KMno, corrected 1? for blank.... Percent Iron in Unknown Average Percent Iron Relative range (ppt).... True Value (provided by instructor). Relative Error (ppt).. Grade. Show calculations for normality of KMno, and Iron in Unknown:

Explanation / Answer

For standardization:

We have to find first average for trial values and then deviation and then average deviation, and finally relative average deviation that's also define as parts per thousand or relative range.

So, average= 100.8+100.9+100.3/3= 100.67%

Deviation=|average -observed value|

Deviation=|100.67-100.8|+|100.67-100.9|+|100.67-100.3|

Then average it .So average deviation= 0.133+0.23+0.37/3

=0.244%

Then relative range (ppt)= average deviation /average*1000= 0.244/100.67 *1000 = 2.43.

For unknown:

Average= 200.1+203+200.2/3= 201.1%

Deviation= |201.1-200.1|+|201.1-203|+|201.1-200.2|

Average deviation= 1+1.9+0.9/3= 1.266%

Relative range(ppt)= 1.26/201.1*1000= 6.29.

Relative range are unit less quantity.

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