(1) Chapter 12 Question 2 - Algorithmic Part A How many kJ of heat are needed to
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(1) Chapter 12 Question 2 - Algorithmic
Part A
How many kJ of heat are needed to completely vaporize 43.2 g of H2O? The heat of vaporization for water at the boiling point is 40.6 kJ/mole.
How many kJ of heat are needed to completely vaporize 43.2 g of H2O? The heat of vaporization for water at the boiling point is 40.6 kJ/mole.
(2) Chapter 12 Question 3 - Algorithmic
Part A
A 250 gram sample of water at the boiling point had 24.0 kJ of heat added. How many grams of water were vaporized? Heat of vaporization for water is 40.6 kJ/mole.
A 250 gram sample of water at the boiling point had 24.0 kJ of heat added. How many grams of water were vaporized? Heat of vaporization for water is 40.6 kJ/mole.
(3)
Chapter 12 Question 21 - True/False
Part A
Water has a heat of vaporization of 44.0 kJ/mol while the chemical diethyl ether has a heat of vaporization of 27.1 kJ/mol. This shows that one mole of water would vaporize more easily than would one mole of diethyl ether.
Water has a heat of vaporization of 44.0 kJ/mol while the chemical diethyl ether has a heat of vaporization of 27.1 kJ/mol. This shows that one mole of water would vaporize more easily than would one mole of diethyl ether.
(4)
Exercise 11.97
Part A
How many grams of calcium are consumed when 160.4 mL of oxygen gas, measured at STP, reacts with calcium according to the following reaction?
2Ca(s)+O2(g)2CaO(s)
(5)
Exercise 11.79
A gas mixture contains 74% nitrogen and 26% oxygen.
Part A
If the total pressure is 1.18 atm what are the partial pressures of each component?
Express your answers using TWO significant figures. Enter your answers numerically separated by a comma.
a. 97.4 b. 2.26 c.16.9 d. 43.2 e. none of the aboveExplanation / Answer
1)
mass of H2O = 43.2 g
molar mass of H2O = 18 g/mol
number of moles of H2O,
n = mass / molar mass
= 43.2/18
= 2.4 mol
Heat required = Hvap * mol
= 40.6 KJ/mol* 2.4 mol
= 97.44 KJ
Answer: a
I am allowed to answer only 1 question at a time
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