(1) Chapter 15 Question 22 - Multiple Choice When writing the expression for an
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(1) Chapter 15 Question 22 - Multiple Choice
When writing the expression for an equilibrium constant, which type of substance IS included?
(2) Chapter 15 Question 23 - Multiple Choice
For the reaction 2 H2O (l) 2H2 (g) + O2 (g), the equilibrium expression is:
(3)Chapter 15 Question 24 - Multiple Choice
For the reaction Cu2S(s) 2Cu+(aq) + S2(aq), the equilibrium expression is:
(4) Chapter 15 Question 37 - True/False
In an exothermic reaction, you can consider the emitted heat as a reactant in this system.
(5) Chapter 15 Question 38 - True/False
Adding heat to an endothermic reaction causes the reaction to shift to the right.
(6) Chapter 15 Question 40 - True/False
If the equilibrium constant, , for a reaction increases upon heating, the reaction must have been endothermic.
(7) Chapter 15 Question 39 - True/False
Adding heat to an exothermic reaction will cause the reaction to remain unchanged.
(8)
Chapter 16 Reading Quiz Question 3
Consider the reaction below. 2 Al(s) + 3 Sn2+(aq) 2 Al3+(aq) + 3 Sn(s) Which of the following is the reducing agent?
(9) Chapter 16 Question 15 - True/False
The oxidation number of a chlorine atom is -1.
(10) Chapter 15 Question 19 - Multiple Choice
Which of the following is TRUE of a system for which >> 1?
(11) Chapter 15 Question 13 - Multiple Choice
For the reaction 2A + B 2C + 3D, the equilibrium expression is:
(12) Chapter 15 Question 14 - Multiple Choice
The chemical equation that would generate the equilibrium expression Keq=[B]2[C][A]3 is ________. (Assume all substances are gases in this reaction.)
a. solids b. gases c. pure liquids d. all of the above e. none of theseExplanation / Answer
1)
pure solids and pure liquids are not included
aqueous and gases are included
Answer: b
2)
dont include liquid
Answer:
a. Keq = [H2]^2 [O2]
3)
don't include solid
Answer:
d. Keq = [Cu+]^2[ S2?]
4)
Since heat is released. it should be on the product side
Answer: False
I am allowed to answer only 1 question at a time
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