Potassium ferrocyanide (n=1) has a diffusion coefficient of 6.5 x 10-6 cm2/s dur

Question

Potassium ferrocyanide (n=1) has a diffusion coefficient of 6.5 x 10-6 cm2/s during its oxidation in 0.1 M KCl. It was used to measure the area of a stationary disk electrode. At a scan rate of 100 mV/s the anodic peak current for the oxidation of 1.0 mM solution of potassium ferrocyanide was 32 A. Estimate the electrode area. Potassium ferrocyanide (n=1) has a diffusion coefficient of 6.5 x 10-6 cm2/s during its oxidation in 0.1 M KCl. It was used to measure the area of a stationary disk electrode. At a scan rate of 100 mV/s the anodic peak current for the oxidation of 1.0 mM solution of potassium ferrocyanide was 32 A. Estimate the electrode area. Potassium ferrocyanide (n=1) has a diffusion coefficient of 6.5 x 10-6 cm2/s during its oxidation in 0.1 M KCl. It was used to measure the area of a stationary disk electrode. At a scan rate of 100 mV/s the anodic peak current for the oxidation of 1.0 mM solution of potassium ferrocyanide was 32 A. Estimate the electrode area.

Explanation / Answer

We know ip = (2.69E5) n^3/2 x A D^1/2 v^1/2 C

Here ip is the peak current n is number of elctrons , A is the electrode area, V is scan rate , c is the concentration of species

Lets plug in the values

A = ip / (2.69E5) n^3/2 x D^1/2 x v^1/2 x C

= 32mA / ( (2.69E5) 1^3/2 x (6.5E-6)^1/2 x (100)^1/2 x 1.0 mM

= 1.18959E-05 cm^2

Answer is 1.18959E-05 cm^2

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