a llsession.masteringchemistry.com/myct/itemviewnassignmentProblemID 68092905 UN

Question

a llsession.masteringchemistry.com/myct/itemviewnassignmentProblemID 68092905 UNCG CHE 111-03-FALL 2016 Post Lecture Homework chapter 11 t Gas Density and Molar Mass previous 13 of 26 Part A t Gas Density and Molar Mass calculate the density of orygen, O2, under each the following oonditions: Pressure and temperature affect the amount of space between gas molecules, which affects the 1.00 atm and 30.0 °C volume and, therefore, the density of the gas since Express your answers numerically in grams per liter. Enter the density at STP first and separato density your answers by a comma. The molar mass of a substance, however, is a constant and can be used to identify an unknown gas sample. Molar mass is found by dividing the mass of a sample (in grams) by the number of moles in that sample. The number of moles of gas can be calculated using the ideal gas law density at STP density at 1 atm and 30.0 1.29, 28.91 which can be rearranged as Submit Hints My Answers Give Up Review Part Given the number of moles of a gas and its molar incorrect; Try Again; 4 attempts remaining mass, you can calculate the mass of the gas. Since density is equal to the ratio of the mass and volume, you can then divide by the volume to find Part B Alternatively, you can use the ratio n/V from the To identify a diatomic gas (X2), a researcher carried out the following experiment: She weighed an ideal gas equation where n is the number of moles empty 2.0-L bulb, then filled it with the gas at 1.00 atm and 26.0 Cand weighed it again. The and V is the volume, and convert from moles per difference in mass was 2.3 g.ldentify the gas. unit volume to grams per unit volume using molar Express your answer as a chemical formula.

Explanation / Answer

1 mole of any gas at STP occupies 22.4 Liters

1 mole of oxygen refer to 32 gm

32 gm occupies 22.4 L at STP

density = 32/22.4 = 1.43 g/cc

from gas law , PV= nRT

PV= (mass/molar mass)*RT

P* molar mass= density*RT, T= 30+273.15= 303.15

density= P* molar mass/RT = 1* 32/(0.0821*303.15)=1.289 g/cc

2. moles of gas = PV/RT

P= 1 atm, V= 2L and R= 0.0821 L.atm/mole.K T= 26+273.15= 299.15K

moles of gas = 1*2/(0.0821*299.15) =0.0814

the difference in mass is due to the mass occupied by the gas

moles= mass/molar mass

0.0814= mass/molar mass

molar mass = 2.3/0.0814=28 g/mole

The gas is N2.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.