In the figure, a particle moves along a circle in a region of uniform magnetic f
ID: 1259970 • Letter: I
Question
In the figure, a particle moves along a circle in a region of uniform magnetic field of magnitude B = 3.1 mT. The particle is either a proton or an electron (you must decide which). It experiences a magnetic force of magnitude 3.1 x 10-15 N. What are (a) the particle's speed, (b) the radius of the circle, and (c) the period of the motion?
In the figure, a particle moves along a circle in a region of uniform magnetic field of magnitude B = 3.1 mT. The particle is either a proton or an electron (you must decide which). It experiences a magnetic force of magnitude 3.1 x 10-15 N. What are (a) the particle's speed, (b) the radius of the circle, and (c) the period of the motion?Explanation / Answer
a)
Magnetic force is given as
Fm = Bvq
3.1 *10^-15 = 0.031 * e * v
v = 6.24 *10^5 m/s
the speed of particle is 6.24 *10^5 m/s
b)
the particle is electon
as F = mv^2/r
r = m*(6.24 *10^5)^2/3.1 *10^-15
r = 1.145 *10^-4 m
the radius of particle is 1.145 *10^-4 m
c)
T = 2*pi*r/v
T = 2*pi*1.145 *10^-4/6.24 *10^5
T = 1.152 *10^-9 s
the period of the motion is 1.152 *10^-9 s
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