In the figure, a parallel-plate capacitor has square plates of edge length L 3.0
ID: 2035334 • Letter: I
Question
In the figure, a parallel-plate capacitor has square plates of edge length L 3.0 m. A current of 5.1 A charges the capacltor, producing a uniform electric field E between the plates, with perpendicular to the plates. (a) What is the displacement current i through the region between the plates? (b) What is dE/dt in this region? (c) What is the displacement current encircled by the square dashed path of edge length d = 0.60 m? (d) what is·B·d S around this square dashed path? Edge view Top view (a) Number (b) Number (c) Number (d) Number Units Units Units UnitsExplanation / Answer
a) Id = I
= 5.1 A
b) Id = epsilon*dE/dt
==> dE/dt = Id/epsilon
= 5.1/(8.854*10^-12)
= 5.76*10^11 N/(C.s)
c) Id' = Id*A'/A
= 5.1*0.6^2/3^2
= 0.204 A
d) use Apmere's law
integral B.ds = mue*I_enslosed
= 4*pi*10^-7*0.204
= 2.56*10^-7 T.m
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