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In the figure, a parallel-plate capacitor has square plates of edge length L 3.0

ID: 2035334 • Letter: I

Question

In the figure, a parallel-plate capacitor has square plates of edge length L 3.0 m. A current of 5.1 A charges the capacltor, producing a uniform electric field E between the plates, with perpendicular to the plates. (a) What is the displacement current i through the region between the plates? (b) What is dE/dt in this region? (c) What is the displacement current encircled by the square dashed path of edge length d = 0.60 m? (d) what is·B·d S around this square dashed path? Edge view Top view (a) Number (b) Number (c) Number (d) Number Units Units Units Units

Explanation / Answer

a) Id = I

= 5.1 A

b) Id = epsilon*dE/dt

==> dE/dt = Id/epsilon

= 5.1/(8.854*10^-12)

= 5.76*10^11 N/(C.s)

c) Id' = Id*A'/A

= 5.1*0.6^2/3^2

= 0.204 A

d) use Apmere's law

integral B.ds = mue*I_enslosed

= 4*pi*10^-7*0.204

= 2.56*10^-7 T.m

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