A 125.4N carton is pulled up a frictionless baggage ramp inclined at 35.0? above
ID: 1262946 • Letter: A
Question
A 125.4N carton is pulled up a frictionless baggage ramp inclined at 35.0? above the horizontal by a rope exerting a 73.4N pull parallel to the ramp's surface. The carton travels 5.90malong the surface of the ramp.
Calculate the work done on the carton by the rope.
Calculate the work done on the carton by the gravity
What is the net work done on the carton?
Suppose that the rope is angled at 40.6? above the horizontal, instead of being parallel to the ramp's surface. How much work does the rope do on the carton in this case?
Explanation / Answer
work done = Force * displacement * cos(theta)
where theta is the angle between force and displacement
NOw ,
work done by rope = 73.4 * 5.90
work done by rope = 433.1 J
work done by gravity = - 125.4 * 5.90 * sin(35)
work done by gravity = -424.4 J
net work done = 433.1 - 424.4
net work done = 8.73 J
in this case ,
work done by rope = 73.4 * 5.90 * cos(40.6 - 35)
work done by rope = 431 J
the work done by rope is 431 J
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