A ball with a mass of 0.580kg is initially at rest. It is struck by a second bal

Question

A ball with a mass of 0.580kg is initially at rest. It is struck by a second ball having a mass of 0.375kg , initially moving with a velocity of 0.230m/s toward the right along the x axis. After the collision, the 0.375kg ball has a velocity of 0.215m/s at an angle of 36.3? above the x axis in the first quadrant. Both balls move on a frictionless, horizontal surface.

A)What is the magnitude of the velocity of the 0.580kg ball after the collision?

B)What is the direction of the velocity of the 0.580kg ball after the collision?

C)What is the change in the total kinetic energy of the two balls as a result of the collision?

Explanation / Answer

First find the initial velocity of the ball immediatly after it hit the floor............,Vf^2=Vi^2+(2)(g)(d)...... final velocity will be zero since at maximum hight Vf=0,..............(0)^2=(Vi)^2+2(-9,8)(... is (F)(change in T)=M(Vf-Vi),N.B,the 0m/s will be the inistial velocity and will be negetive and the 3,70m/s will the final velocity and will be positve,this you will easily understand it if u do projectiles.,substitution,(F)(change inT)=0,580(3,70-(-0)),therefore the answer is 2,15N/S

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