Chegg Textbook Solutions for Fundamentals of Physics 10th Edition Chapter 8 Prob

Question

Chegg Textbook Solutions for Fundamentals of Physics 10th Edition Chapter 8 Problem 21P

The textbook solutions here in chegg breaks the diagram down using A (the fulcrum), B (the bob at 90 degrees), C (the bob at 40 degrees), and D (the point perpendicular to C along AB) and shows the following:

Therefore, (and this is where I'm stuck)

In the textbook the question is, '' Figure 8-34 shows a pendulum of length L=1.25m. It's bob (which effectively has all of the mass) has speed v0 when the cord makes an angle theta 0 = 40.0 degree with the vertical. (a) What is the speed of the bob when it is in its lowest position if v 0=8.00 m/s? the diagram down using A (the fulcrum), B (the bob at 90 degrees), C (the bob at 40 degrees), and D (the point perpendicular to C along AB) and shows the following: Delta ADC AD=Accos theta AD=Lcos theta BD=L left ( 1-cos theta right ) My question is, where does 1-cos theta come from?

Explanation / Answer

Simple try, trigonometry properties. See what is (1-cos(angle)). the movement of a pendulum is describe like a part of a circle. Then use the relation between the pendulum (the data they provide you) and the parameters of a pendulum and make the relation. There you will see where 1-cos comes from. Have fun

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