Two circular plates with radius 8.22 cm have equal and opposite charge of magnit

Question

Two circular plates with radius 8.22 cm have equal and opposite charge of magnitude 0.552 muC. Calculate the electric field between the two plates. assume that the separation distance is small in comparison to the diameter of the plates.

The plates are slowly pulled apart, doubling the separation distance. What changes occur with the electric field between the plates? (Again, assume the separation distance remains small in comparison to the diameter of the plates.)

A) The electric field increases by a factor of 4
B) The electric field increases by a factor of 2
C) The electirc field stays the same.
D) The electric field decreases by a factor of 2.
E) The electric field decreases by a factor of 4.

Explanation / Answer

Part A)

Start with C = eA/d

C = Q/V and V = Ed.

Q/Ed = eA/d

Q/E = eA

(.552 X 10-6)/E = (8.85 X 10-12)(pi)(.0822)2

E = 2.94 X 106 N/C

Part B)

As you can see, d canceled in the equation above, so the Electric Field has nothing to do with the distance.

Thus the field remains unchanged. Choice C

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