In a proton linear accelerator, a 8.0mA proton current hits a target. 1) How man

Question

In a proton linear accelerator, a 8.0mA proton current hits a target. 1) How many protons hit the target each second? Express your answer using two significant figures. ANSWER IS: 5.0X10^162) How much energy is delivered to the target each second if each proton has a kinetic energy of 27MeV and loses all its energy in the target? Express your answer using two significant figures. ANSWER IS: 2.2x10^5 3) If the target is a 1.60kg block of copper, at what rate will its temperature increase if it is not cooled? Express your answer as an integer.

Explanation / Answer

i = 8.0 mA = 8.0 * 10-3 A

a)No.of protons per second N = 8.0 * 10-3 / ( 1.6* 10-19 )

= 5.0 * 1016

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b) kinetic energy for each proton E = 27 MeV

So, kinetic energy of N protons E ' = NE

= 27 * 5 * 1016 * 1.6 * 10-13 J

= 216000 = 2.2 * 105 J

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c) mass m = 1.6 kg

U = m c delta t

216000 = (1600) * (0.385) * (delta t)

delta t = 350

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