In a proton linear accelerator, a 8.5mA proton current hits a target. How many p

Question

In a proton linear accelerator, a 8.5mA proton current hits a target.
How many protons hit the target each second?
=

How much energy is delivered to the targeteach second if each proton has a kinetic energy of25MeV and loses all its energy in the target?
= J/s
If the target is a 1.70kg block of copper, at what rate will its temperature increase if it is not cooled? = s

Explanation / Answer

Current hitting the target: i = 9.5 *10^-3 A In one second charge = Q = i * 1 = 9.5 *10^-3 C "hits" q = 1.602*10^-19 C --->c proton charge a) # = Q/q # = 9.5 *10^-3/(1.602*10^-19) ˜ 5.93*10^16 Since we cannot have a fractional proton b) Energy ˜ 20*# ˜ 20*5.93*10^16 ˜ 1.186*10^18 Mev /s OR :˜ 190018.128 J /s

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