The electron gun in an old TV picture tube accelerates electrons between two par

Question

The electron gun in an old TV picture tube accelerates electrons between two parallel plates 1.0cm apart with a 23kV potential difference between them. The electrons enter through a small hole in the negative plate, accelerate, then exit through a small hole in the positive plate. Assume that the holes are small enough not to affect the electric field or potential. part A What is the electric field strength between the plates? Express your answer to two significant figures and include the appropriate units. E= Part B With what speed does an electron exit the electron gun if its entry speed is close to zero? Express your answer to two significant figures and include the appropriate units. V exit=

Explanation / Answer

EF E = V/d

E = 23000/(0.01))

E = 2.3 *10^6 N/C
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B .

0.5 mv^2 = eV

v^2 = 1.6e-19 * 23000*2/(9.11e-31)

V = 8.9 *10^7 m/s

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