A golf ball is hit off a tee at the edge of a cliff. Its x and y coordinates as

Question

A golf ball is hit off a tee at the edge of a cliff. Its x and y coordinates as functions of time are given by

x = 17.1t

and

y = 3.88t ? 4.73t2,

where x and y are in meters andt is in seconds.

By taking derivatives, do the following. (Give the answers in terms of t.)

A golf ball is hit off a tee at the edge of a cliff. Its x and y coordinates as functions of time are given by x = 17.1t and y = 3.88t ? 4.73t^2, where x and y are in meters andt is in seconds. By taking derivatives, do the following. (Give the answers in terms of t.) (b) obtain the expression for the velocity vector v with arrow as a function of time v with arrow = (c) obtain the expression for the acceleration vector a with arrow as a function of time a with arrow = (d) Next use unit-vector notation to write expressions for the position, the velocity, and the acceleration of the golf ball at t = 3.03 s.

Explanation / Answer

B) Vx = dx/dt = 17.1 m/sec...

Vy = dy/dt = 3.88-(2*4.73*t) = 3.88-9.46t...

C) ax = 0 ms^-2...

ay = -9.46 ms^-2...

D) x = 17.1*3.03 = 51.813 m i hat...
   y = 3.88*3.03 - (4.73*3.03*3.03) = -31.67 m j hat..

Vx = 17.1 m/sec i hat...

Vy = -24.78 m/sec j hat....

ax = 0 ms^-2 i hat...

ay = -9.46 ms^-2 j hat

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