A golf ball is hit off a tee 3t the edge of a cliff. Its x and y coordinates as

Question

A golf ball is hit off a tee 3t the edge of a cliff. Its x and y coordinates as functions of time are given by x = 17.8t and y = 3.92t - 5.05t2, where x and y are in meters and t is in seconds. Write a vector expression for the ball's position as a function of time, using the unit vectors 3nd . (Give the answer in terms of t.) By taking derivatives, do the following. (Give the answers in terms of t.) obtain the expression for the velocity vector v as a function of time obtain the expression for the acceleration vector a as a function of time Next use unit-vector notation to write expressions for the position, the velocity, and the acceleration of the golf ball at t = 2.97 s.

Explanation / Answer

a) 17.8*t i + [3.92*t - 5.05*(t^2) ] j b) 17.8 i +(3.92 - 10.1*t) j c) acceleration = - 10.1 j d) r = 52.87 i - 32.903 j v = 17.8 i - 26.077 j acceleration = -10.1 j

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