The loop in the figure is being pushed into the 0.20 T magnetic field at 50 m/s.

Question

The loop in the figure is being pushed into the 0.20 T magnetic field at 50 m/s.The resistance of the loop is 0.35?.

A) What is the magnitude of the current in the loop?

B) What is the direction of the current in the loop? Clockwise or Counterclockwise?

The loop in the figure is being pushed into the 0.20 T magnetic field at 50 m/s.The resistance of the loop is 0.35?. A) What is the magnitude of the current in the loop? B) What is the direction of the current in the loop? Clockwise or Counterclockwise?

Explanation / Answer

V = vLXB = 50*0.05*0.2 = 0.5 V
The direction is determined by the cross-product.
v is up, B is out of the plane, thus V and I are to the right along the advancing side thus clockwise around the loop.
a) I = V/R = 1.42857 A

b)  clockwise

v is up, B is out of the plane, thus V and I are to the right along the advancing side thus clockwise around the loop.

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