The loop in Figure 18 is being pushed into the 0.20 T magnetic field at 50 m/s.
ID: 2257457 • Letter: T
Question
The loop in Figure 18 is being pushed into the 0.20 T magnetic field at 50 m/s. The resistance of the loop is 0.100W.
What are the direction and magnitude of the current in the loop?
Explanation / Answer
V = d(BA)/dt = B*v*w
i*0.1 = 0.2*50*0.05
i = 5A
direction = clockwise,
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.