A ball of mass 0.448kg moving east (+x direction) with a speed of 3.86m/s collid

Question

A ball of mass 0.448kg moving east (+x direction) with a speed of 3.86m/s collides head-on with a 0.224kg ball at rest. Assume that the collision is perfectly elastic.

Part A

What is be the speed of the 0.448-kg ball after the collision?

Part B

What is be the direction of the velocity of the 0.448-kg ball after the collision? to the east or to the west

Part C

What is the speed of the 0.224-kg ball after the collision?

Part D

What is the direction of the velocity of 0.224-kg ball after the collision? to the east or to the west

Explanation / Answer

a) velocity of ball of mass 0.448Kg = ((0.448-0.224)/(0.448+0.224))*3.86 = 1.2867 m/s      (condition of ealastic collision)

b) velocity is positive so it will move in the direction of previous direction means in east direction

c) velocity of ball of mass 0.224Kg = Ma*(Vf-Vi)/Mb = 0.448*(3.86-1.2867)/0.224 = 5.1466m/s       (from momentum equation)

d) velocity is positive means it will also move in east direction.

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