In the figure, R = 1.8k? and ? 0 = 48V . When the switch is closed, the current

Question

In the figure, R = 1.8k? and ?0 = 48V . When the switch is closed, the current through the inductor rises to 10mA in 20?s.

a. What is the inductance?

b. What will the current in the circuit be after many time constants?

Other chegg answers for this question are incorrect so don't reference them.

In the figure, R = 1.8k? and ?0 = 48V . When the switch is closed, the current through the inductor rises to 10mA in 20?s. a. What is the inductance? b. What will the current in the circuit be after many time constants? Other chegg answers for this question are incorrect so don't reference them.

Explanation / Answer

I(t) = V/R ( 1- e^ (-Rt/L))

10 x 10-3 = 48 / 1800 ( 1 - e^ ( - 1800 x 20 x 10-6 / L))

e^ ( - 1800 x 20 x 10-6 / L) = 0.625

taking ln both side

- 1800 x 20 x 10-6 / L = ln(0.625)

L = 0.0766 H or 76.6 mH

b) after so many ,

I = 48/1800 = 0.0267 A or 26.7 mA

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