A photon is emitted when a hydrogen atom undergoes a transition from the n = 12
ID: 1295414 • Letter: A
Question
A photon is emitted when a hydrogen atom undergoes a transition from the n = 12 state to the n = 3 state. Calculate values for the following.A. The wavelength (in NM) B. The frequency (in Hz) C. The energy of the emitted photon A photon is emitted when a hydrogen atom undergoes a transition from the n = 12 state to the n = 3 state. Calculate values for the following.
A. The wavelength (in NM) B. The frequency (in Hz) C. The energy of the emitted photon
A. The wavelength (in NM) B. The frequency (in Hz) C. The energy of the emitted photon
Explanation / Answer
Transition from n= 12 to n=3
By formula:
1/L = R*((1/n1)2 - (1/n2)2)
L = wavelength
n1 = 3
n2 = 12
R= 1.097 * 107 m-1
So, 1/L = 1.097 * 107 * (1/9 - 1/144) = 0.114 * 107
or L = 8.77 * 10-7 m = 877 nm (wavelength)
Frequency = c/L = 0.34 * 1017 Hertz = 3.4 * 1016 hz
Energy = hf = 3.4 * 1016 * 6.636 * 10-34 = 22.56 * 10-18 J = 2.25 * 10-17 J
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