When a system is taken from state a to state b in the figure (Figure 1) along th

Question

When a system is taken from state a to state b in the figure (Figure 1) along the path acb, 83.0J of heat flows into the system and 52. 0J of work is done by the system. how much heat flows into the system along path adb if the work done by the system is 15. 0J ? When the system is returned from 6 to a along the curved path, the absolute value of the work done by the system is 33.OJ . Does the system absorb or liberate heat? How much heat? If Ua = 0 and Uj = 8.00J . find the heat absorbed in the processes ad and db

Explanation / Answer

Part A:

deltaU along path acb : 83 - 52 J= 31 J

deltaU along path adb : 31 = Q - 15

hence Q along path adb = 46 J

Part B:

deltaU = -31 = Q + W

W = -33 J (work done by the system)

so, Q = -31 + 33 J = 2 J,

hence heat is absorbed by the system.

Part C:

Q = 2 J

Part D:

deltaU = q + W

W = -15 J (as mentioned in part A, there is no work done along the path db - no change in the volume)

so

deltaU = 8 = q - 15

hence, q = 23 J

Part E:

deltaU along path db = deltaU from a to b - deltaU from a to d

deltaU = 31 - 8 J = 23 J

hence 23 = q + 0

so, q along path db = 23 J

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