When a system is taken from state a to state b in the figure (Figure 1) along th

Question

When a system is taken from state a to state b in the figure (Figure 1) along the path acb, 85.0 J of heat flows into the system and 63.0 J of work is done by the system.

Part A

How much heat flows into the system along path adb if the work done by the system is 19.0 J ?

Part B

When the system is returned from b to a along the curved path, the absolute value of the work done by the system is 30.0 J . How much heat does the system liberate?

Part C

If the internal energy is zero in state a and 8.0 J in state d, find the heat absorbed in the processes ad.

Part D

Find the heat absorbed in the processes db.

Explanation / Answer

for path acb

dQ = dU + dW

85 = dU + 63

dU = 85-63 = 22 J

part A

dQ = dU + dW

dQ = 22 + 19 = 41 J <<<<<------answer

++++++++++++++++

part (B)

dQ = dU - dW

dQ = 22 - 30 = -8 J <<<<<------answer

++++++++++

part (C0

dQad = (8-0) + 63 = 71 J   <<<<<------answer

part(D)

dQ = dU + dW

since volume is constant dw = 0

dU = 22-8 = 14 J

dq = 14 J <<<<<------answer

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