When a system is taken from state a to state b in the figure along the path acb,

Question

When a system is taken from state a to state b in the figure along the path acb, 90.0J of heat flows into the system and 50.0J of work is done by the system. If Ua=0 and Ud = 6.00J, find the heat absorbed in the processes ad and db . *For db i got the right answer which is 34J I tried 2,6, and 36 for ad, but they are wrong answers... can plz someone get it right??

When a system is taken from state a to state b in the figure along the path acb, 90.0J of heat flows into the system and 50.0J of work is done by the system. If Ua=0 and Ud = 6.00J, find the heat absorbed in the processes ad and db . *For db i got the right answer which is 34J I tried 2,6, and 36 for ad, but they are wrong answers... can plz someone get it right??

Explanation / Answer

I will give answer only for the path. i think you have managed the path bd

Now let path adb be reversed, so we get a cycle acbd

Qbd = - 34 J

also for a cycle : U = 0

W = Q

Wac + Wcb + Wbd + Wda = Qac + Qcb + Qbd+ Qda

Qac + Qcb = Qacb = 90 J given

Wac + Wcb = wacb = 50 J

Wbd = o, constant volume

50 + Wda + 0 = 90 - 34 + Qda

Wda = 6 + Qda

now area under cycle = 40 J

area under curve cb = 50 J, as wcb = 50J

area under curve = ad = 50 - 40 = 10 J = Wda

10 = 6 + Qda

Qda = 4J

or Qad = -4J

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