Two friends A and B stand in wind blowing from A to B. A beats a drum and B hear

Question

Two friends A and B stand in wind blowing from A to B. A beats a drum and B hears the sound t1 time after he sees the event. A and B interchange their positions and the experiment is repeated. This time B hears the drum t2 time after he sees the event. Calculate the velocity of sound in still air v and the velocity of the wind u. Then, A and B change their positions in such a way that the line joining them becomes perpendicular to the direction of wind while maintaining the seperation x.What will be the time lag B finds in seeing and hearing? Neglect the time light takes in travelling between the friends.

Explanation / Answer

t1 = AB/(u+v) , t2 = AB/(v-u)

u = AB/2*t1*t2/(t1-t2) , v = AB/2*t1*t2/(t1+t2)

Time lag for second case = AB/(v2 - u2).5

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