Two forces, of magnitudes = 100 and = 45.0 , act in opposite directions on a blo

Question

Two forces, of magnitudes = 100 and = 45.0 , act in opposite directions on a block, which sits atop a frictionless surface, as shown in the figure. (Figure 1) Initially, the center of the block is at position = -6.0
At some later time, the block has moved to the right, and its center is at a new position, = 4.00 .



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A. Find the work done on the block by the force of magnitude = 100 as the block moves from = -6.00 to = 4.00 .
Express your answer numerically, in joules.


B. Find the work done by the force of magnitude = 45.0 as the block moves from = -6.00 to = 4.00 .
Express your answer numerically, in joules.


C. What is the net work done on the block by the two forces?
Express your answer numerically, in joules.


D. Determine the change in the kinetic energy of the block as it moves from = -6.00 to = 4.00 .
Express your answer numerically, in joules.

Explanation / Answer

a) W = 100*0.10 = 10 J

b) W = -45*0.10 = -4.5 J

c) 10.00 - 4.50 = 5.5 J

d) K = 5.5 J

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