Consider the 65.0-kg ice skater being pushed by two others shown in Figure 7. (a

Question

Consider the 65.0-kg ice skater being pushed by two others shown in Figure 7. (a) Find the direction and magnitude of Ftot, the total force exerted on her by the others, given that the magnitudes F1 and F2 are 28.8 N and 16.6 N, respectively. (b) What is her initial acceleration if she is initially stationary and wearing steel-bladed skates that point in the direction of Ftot? (c) What is her acceleration assuming she is already moving in the direction of Ftot? (Remember that friction always acts in the direction opposite that of motion or attempted motion between surfaces in contact.)

Explanation / Answer

Part A)

Net force is from the Pythagorean Theorem

F2 = (28.8)2 + (16.6)2

F = 33.24 N

Part B)

F = ma

33.24 = 65(a)

a = .511 m/s2

Part C)

Same as part B

F = ma

33.24 = 65(a)

a = .511 m/s2

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