A football wide receiver rushes 16 m straight down the playing field in 2.9 s (i

Question

A football wide receiver rushes 16 m straight down the playing field in 2.9 s (in the positive direction). He is then hit and pushed 2.5 m straight backwards in 1.65 s. He breaks the tackle and runs straight forward another 24 m in 5.2 s.

Part (a) Calculate the wide receiver's average velocity in the horizontal direction during the first interval, in meters per second.

Part (b) Calculate the wide receiver's average velocity in the horizontal direction during the second interval, in meters per second.

Part (c) Calculate the wide receiver's average velocity in the horizontal direction during the third interval, in meters per second.

Part (d) Calculate the wide receiver's average velocity in the horizontal direction for the entire motion, in meters per second.

Explanation / Answer

apply the formula for velocity v = displacement/time

so here

for first run, V1 = S1/t1 = 16/2.9 = 5.517 m/s-------------------ANswer to A

for second run, V2 = S2/t2 = 2.5/1.65 = 1.515 m/s-------<<<<<<answer to B

for third run, V3 = S3/t3 = 24./5.2 = 4.61 m/s ---------------<<<<<<<<<<<Answer to C

for entire run,

Vavg = Vnet displacemnt /total time

vavg = (16 -2.5+24)/(2.9+1.65 + 5.2)

Vavg = 3.84 m/s -----------<<<<<<<<<<<<Answer to part D

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