A battery is connected in series with a 0.31-12 resistor and an inductor, as sho
ID: 1333599 • Letter: A
Question
A battery is connected in series with a 0.31-12 resistor and an inductor, as shown in the figure below. The switch is closed at t = 0. The time constant of the circuit is 0.30 s, and the maximum current in the circuit is 7.9 A. Find the emf of the battery. V Find the inductance of the circuit. mH Find the current in the circuit after one time constant has elapsed. (Round your answer to four decimal places.) Find the voltage across the resistor after one time constant has elapsed. (Round your answer to four decimal places.) differs from the correct answer by more than 10%. Double check your calculations. V Find the voltage across the inductor after one time constant has elapsed.Explanation / Answer
V ( = 1) = (V * e^-(R/L * t)) / R = (2.449 * e^-1) / R = 0.9007422 V / 0.31 = 2.90562Amps
(d) V = I * R = 2.90562 Amps * 0.31 ohms = 0.9007422 V
(e) V = VR + VL; 2.449 Volts = 0.9007422 V + VL ; VL = 1.5482578 Volts
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