How does the pressure exerted by a liquid change with the depth of the liquid? H

ID: 1337779 • Letter: H

Question

How does the pressure exerted by a liquid change with the depth of the liquid?
How does the pressure exerted by a liquid change as the density of the liquid changes?
Discounting the pressure of the atmosphere, if you swim twice as deep in water, how much more water pressure is exerted on your ears?
In a deep dive, a whale is appreciably compressed by the pressure of the surrounding water. What happens to the whale’s density?
If water faucets upstairs and downstairs are turned fully on, will more water per second flow out the downstairs faucet? Or will the flows from the faucets be the same?

How does the pressure exerted by a liquid change with the depth of the liquid?
How does the pressure exerted by a liquid change as the density of the liquid changes?
Discounting the pressure of the atmosphere, if you swim twice as deep in water, how much more water pressure is exerted on your ears?
In a deep dive, a whale is appreciably compressed by the pressure of the surrounding water. What happens to the whale’s density?
If water faucets upstairs and downstairs are turned fully on, will more water per second flow out the downstairs faucet? Or will the flows from the faucets be the same?

Pressure exerted by the liquid is

P = (density of water ) g h

Here, g is acceleration due to gravity and h is depth.

From the above formula pressure is proportional to the density of the liquid and depth.

As the depth increases, pressure increases.

Pressure exerted by the liquid increases as the density of the liquid increases.

Pressure exerted on ear is

P = F / A

= force exerted by the water on ear / area of ear

= ( density of water ) (volume of ear) g / area of ear

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The downward gravitatonal force is more than up ward buoyant force on the whale. so

mg > ( densityo of water ) (volume of whale ) g

density of whale is > density of water

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