An electron travels at a speed of 1.0×10 4 m/sthrough a uniform magnetic field w

Question

An electron travels at a speed of 1.0×104 m/sthrough a uniform magnetic field whose magnitude is 1.1×103 T .

1. What is the magnitude of the magnetic force on the electron if its velocity and the magnetic field are perpendicular?

2.   What is the magnitude of the magnetic force on the electron if its velocity and the magnetic field make an angle of 45 ?

3. What is the magnitude of the magnetic force on the electron if its velocity and the magnetic field are parallel?

4 What is the magnitude of the magnetic force on the electron if its velocity and the magnetic field are exactly opposite?

Explanation / Answer

F = qVxB = qVB sin( theta)

1. F = 1.6*10^-19*10^4*1.1*10^-3 = 1.76e-18 N

2. F = 1.6*10^-19*10^4*1.1*10^-3*0.707 = 1.24432e-18 N

3. 0

4. 0

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