An electron moving to the right at5.0% the speed of light enters auniform electr

Question

An electron moving to the right at5.0% the speed of light enters auniform electric field parallel to its direction of motion. If theelectron is to be brought to rest in the space of 5.7 cm, determine the following. (b) What is the strength of the field?
2 N/C
An electron moving to the right at5.0% the speed of light enters auniform electric field parallel to its direction of motion. If theelectron is to be brought to rest in the space of 5.7 cm, determine the following. (b) What is the strength of the field?
2 N/C

Explanation / Answer

An electronmoving to the right at 5.0% the speed of light enters a uniform electric
field parallel to its direction of motion. If the electron is to bebrought to rest in the
space of 5.7 cm, determinethe following. (b) What isthe strength of the field?

Electron will stop when E-Field hasdone work on the electron equal
to electron's initial Kinetic Energy:

     {Initial Electron Kinetic Energy} = {Work Done On Electron By E-Field}

     ---->   (1/2)*m*v^2 = Q*E*x

     ---->    E = ((1/2)*m*v^2)/(Q*x)

     ---->    E = ((1/2)*(9.109e-31 kg)*((0.05)*(2.998e+8m/sec))^2)/((1.602e-19C)*(5.7e-2 m))

   ---->    E = 11207 N/C

.

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