A 13.0 F capacitor is connected to a power supply that keeps a constant potentia

Question

A 13.0 F capacitor is connected to a power supply that keeps a constant potential difference of 24.0 V across the plates. A piece of material having a dielectric constant of 3.60 is placed between the plates, completely filling the space between them. PLEASE TAKE YOUR TIME AND SOLVE THE ANSWERS ARE NOT 13.32 AND 9.62
Part A
How much energy is stored in the capacitor before the dielectric is inserted?

Part B
How much energy is stored in the capacitor after the dielectric is inserted?

Part C
By how much did the energy change during the insertion?

Explanation / Answer

The energy stored in the capacitor before the dielectric is inserted is given by

U1 =(1/2)CV2 =0.5*13*10-6*(24)2 =3744*10-6 =3.744*10-3J

b)

The energy stored in the capacitor after the dielectric of 3.60 is inserted then energy incresaes 3.60 times

U2 =3.60*(1/2)CV2 =3.60*0.5*13*10-6*(24)2 =3.60*3744*10-6 =3.60*3.744*10-3J=13.4784*10-3J

c)

The difference in energy change is U2-U1 =13.4784*10-3J-3.744*10-3J =9.7344*10-3J

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