In Procedure 1: a wire of length L = 5.22 cm sits on an electronic scale. There

Question

In Procedure 1: a wire of length L = 5.22 cm sits on an electronic scale. There is also a uniform mangetic field perpendicular to the wire, and along its entire length. When there is no current in the wire, the scale reads 938 g. When a current I = 19 mA goes through the wire, and the scale reads 893 g. NOTE: Beware of units! NOTE: These numbers are not like the numbers you will actually get when you do the expermiment!

a) Find the magnitude of the force on the wire created by the interaction of the current and the magnetic field. F =

b) Find the magnitude of the magnetic field around the wire. B =

c) Suppose the direction of the magnetic field is reversed. What would the scale read now? m = g d) Suppose the system could take large currents. To what would you have to raise the current (before you reversed the direction of B) so the force on the wire entirely supported the weight of the wire (and the scale reads zero)? I =

Explanation / Answer

F=(0.938-0.893)*9.8=0.441 N

magnetic force F=BiL

B=F/IL=444.65 T

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.