A 0.24-kg block is held in place against the spring by a 60-N horizontal externa

Question

A 0.24-kg block is held in place against the spring by a 60-N horizontal external force (see the figure). The external force is removed, and the block is projected with a velocity v 1 = 1.2 m/s upon separation from the spring. The block descends a ramp and has a velocity v 2= 2.1 m/s at the bottom. The track is frictionless between points A and B. The block enters a rough section at B, extending to E. The coefficient of kinetic friction over this section is 0.34. The velocity of the block is v 3 = 1.4 m/s at C. The block moves on to D, where it stops. The initial compression of the spring is closest to: A satellite that weighs 4900 N on the launchpad travels around the earth's equator in a circular orbit with a period of 1.667 h. The earth's mass is 5.97 Times 10^24 kg. its equatorial radius is 6.3 Times 10^6 m, and G = 6.67 Times 10^-11 N m^2/kg^2. Calculate the magnitude of the earth's gravitational force on the satellite. Determine the altitude of the satellite above the Earth's SURFACE.

Explanation / Answer

Qns 1 )

W = change in KE

W = F.x

F.x = 1/2 * m ( 2.1^2 - 1.2^2)

x = .59 m = 0.58 cm

qns 2 )

part a )

F = GM*m/r^2

m = 500 kg

M = 5.97 x 10^24

r = 6.3 x 10^6 m

F = 5016.36 N

part b )

R^3 = T^2 * GM/4*pi^2

T = 1.667h = 1.667 x 3600 s

R = 7.135 x 10^6 m

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