A 0.24-kg rock is held 1.1 m above the top edge of a water well and then dropped

Question

A 0.24-kg rock is held 1.1 m above the top edge of a water well and then dropped into it. The well has a depth of 4.6 m.

(a) Relative to the configuration with the rock at the top edge of the well, what is the gravitational potential energy of the rockEarth system before the rock is released?

(b) Relative to the configuration with the rock at the top edge of the well, what is the gravitational potential energy of the rockEarth system when it reaches the bottom of the well?

(c) What is the change in gravitational potential energy of the system from release to reaching the bottom of the well?

Explanation / Answer

A) Before release, PE1 = m g h = 0.24 X 9.81 X 1.1 = 2.59 J

B) After release, PE2 = m g h = 0.24 X 9.81 X (-4.6) = -10.83 J

C) Delta PE = PE1 - PE2 = -10.83 - 2.59 = -13.42 J

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