Find the equivalent resistance of the circuit The current through each resistor
ID: 1373049 • Letter: F
Question
Find the equivalent resistance of the circuit
The current through each resistor
The voltage across the 8 Ohm resistor
The power generated by the battery
The power dissipated in the 6 Ohm resistor
Find 1. The equivalent resistance of the circuit . 2. The current through each resistor 3. The voltage across the 8 Ohm resistor 4. The power generated by the battery 5. The power dissipated in the 6 Ohm resistor Find the equivalent resistance of the circuit The current through each resistor The voltage across the 8 Ohm resistor The power generated by the battery The power dissipated in the 6 Ohm resistorExplanation / Answer
1) Here, 4 and 6 ohm resistors are connecetd in parallel
R(4,6) = 4*6/(4+6)
= 2.4 ohms
This, combination is connected in series with 5 ohm
R(4,5,6) = 2.4 + 5
= 7.4 ohms
This comination is parallel with 8 ohms
so, Rnet = 7.4*8/(7.4+8)
= 3.84 ohms <<<<<<<<------------Answer
2) Inet = V/R
= 18/3.84
= 4.68 A
I(8) = Inet*7.4/(7.4+8)
= 4.68*7.4/(7.4+8)
= 2.25 A <<<<<<<<------------Answer
I(5) = Inet - I(8)
= 4.68 - 2.25
= 2.43 A <<<<<<<<------------Answer
I(6) = I(5)*4/(6+4)
= 0.972 A <<<<<<<<------------Answer
I(4) = I(5) - I(6)
= 2.43 - 0.972
= 1.458 A <<<<<<<<------------Answer
3) V(8) = 18 volts (beacause in it connected in parallel)
4) P = V^2/(Rnet)
= 18^2/(3.84)
= 84.4 Watts <<<<<<<<------------Answer
5) P(6) = I(6)^2*6
= 0.972^2*6
= 5.67 Watts <<<<<<<<------------Answer
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