A ladder of length 20.0m is carried by a fire truck. The ladder has a weight of

Question

A ladder of length 20.0m is carried by a fire truck. The ladder has a weight of 2500N and its center of gravity is at its center. The ladder is pivoted at one end (A) about a pin (Figure 1) ; you can ignore the friction torque at the pin. The ladder is raised into position by a force applied by a hydraulic piston at C. Point C is a distance 8.0mfrom A, and the force F?  exerted by the piston makes an angle of ? = 40? with the ladder.

Part A

What magnitude must F?  have to just lift the ladder off the support bracket at B?

Express your answer using two significant figures.

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Figure 1 of 1

A ladder of length 20.0m is carried by a fire truck. The ladder has a weight of 2500N and its center of gravity is at its center. The ladder is pivoted at one end (A) about a pin (Figure 1) ; you can ignore the friction torque at the pin. The ladder is raised into position by a force applied by a hydraulic piston at C. Point C is a distance 8.0mfrom A, and the force F?  exerted by the piston makes an angle of ? = 40? with the ladder.

Part A

What magnitude must F?  have to just lift the ladder off the support bracket at B?

Express your answer using two significant figures.

F =   N  

SubmitMy AnswersGive Up

Provide FeedbackContinue

Figure 1 of 1

A ladder of length 20.0m is carried by a fire truck. The ladder has a weight of 2500N and its center of gravity is at its center. The ladder is pivoted at one end (A) about a pin (Figure 1) ; you can ignore the friction torque at the pin. The ladder is raised into position by a force applied by a hydraulic piston at C. Point C is a distance 8.0mfrom A, and the force F? exerted by the piston makes an angle of ? = 40? with the ladder. Part A What magnitude must F? have to just lift the ladder off the support bracket at B? Express your answer using two significant figures

Explanation / Answer

apply torques relative to B, so you will find the force : F

F*sin(40)*8 - 2500*10 = 0

F*sin(40) = 2500*10 / 8

F = 4861.64 Newtons

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