Two idential #14 bulbs and an intially uncharged 1F capacitor are connected to a

Question

Two idential #14 bulbs and an intially uncharged 1F capacitor are connected to an ideal 3V battery as shown.

a) Before the switch is closed what is the potential difference across bulb A, across bulb B, across the capacitor, and across the battery?

b) Just after the switch is closed (a very short time) what is the potential difference across bulb A, bulb B, the capacitor, and the battery?

c) Just after the switch is closed, rank the currents IA, IB, IC, IBAT in decreasing order.

d) A long time after the switch is closed rank the currents IA, IB, IC, IBAT in decreasing order

e) A long time after the swicth is closed what is the potential difference across bulb A, across bulb B, across the capacitor, and across the battery?

f) Can you describe what happens if after a long time the switch is now opened?

Explanation / Answer

a)Initially switch was opened and capacitor was uncharged. (no current anywhere)
So the potential difference across
Battery = 3V, Capacitor = 0, Bulb A = 0, Bulb = 0

b) After short time capacitor take time to charge
Battery = 3V, Capacitor = 0, Bulb A = 3V, Bulb B = 0

c) After short time capacitor take time to charge
So all currents go through capacitor

so rank
IBAT, IA,IC,IB

d) Afterlong time capacitor will be charged
So no currents go through capacitor

so rank
IBAT, IA,IB,IC

e) After long time after the switch is closed
capacitor fully charged and no current
So potential different
Battery = 3V , Bulb A= 1.5 V , Bulb B = 1.5V , Capacitor = 1.5V

f) if after a long time the switch is now opened the capacitor provide energy for some time to Bulb b

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