A block of mass m = 3.40 kg is pushed a distance d = 4.10 m along a frictionless

Question

A block of mass m = 3.40 kg is pushed a distance d = 4.10 m along a frictionless, horizontal table by a constant applied force of magnitude F = 16.0 N directed at an angle theta = 26.0 Degree below the horizontal as shown in the figure below. (a) Determine the work done on the block by the applied force. (b) Determine the work done on the block by the normal force exerted by the table. (c) Determine the work done on the block by the gravitational force. (d) Determine the work done by the net force on the block.

Explanation / Answer

Given,
Mass = 3.4 kg
d= 4.10m
Force = 16 N
angle = 26.0

x component of Force = F cos(theta)

x component of Force = 16 * 0.898 = 14.38 N

a)

Work done due to applied force = F * D
Work done due to applied force =14.38 * 4.10

Work done due to applied force = 59 J

b)

Work done on the block due to normal force = 0 J ,because displacement is zero in that direction.

c)

Work done on the block by gravitational force = 0 J ,because displacement is zero in that direction.

d) Work done by net force = 59 J

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