Chapter 04, Problem 058 A rotating fan completes 1160 revolutions every minute.

Question

Chapter 04, Problem 058 A rotating fan completes 1160 revolutions every minute. Consider the tip of a blade, at a radius of 17.0 cm. (a) Through what distance does the tip move in one revolution? What are (b) the tip's speed and (c) the magnitude of its acceleration? (d) What is the period of the motion? Number (a) Number Units -, Units (b) Number (c) Number Units (d) Number Units Answer * 1: the tolerance is +/-2% Answer * 2: the tolerance is +/-2% Answer 3: the tolerance is +/-2% Answer * 4: the tolerance is +/-2% Question Attempts: 0 of 5 used DeltEnd

Explanation / Answer

angular speed w= 1160 rev / min
= 1160 * 2*pi rad / 60 s = 121.413 rad/s
radius r = 17 cm = 0.17 m
(a). distance moved in one revolution S = 2*pi*r = 2*3.14*0.17
=1.0676 m
(b)tip's.Speed v = r w = 0.17*121.413
= 20.64 m / s
(c).Magnitude of the accleration a = v^ 2/ r =( 20.64 )^2/0.17
= 2506 m / s^ 2
(d).Period T = 2*pi/ w
= 2*3.14i / 121.413
= 0.052 s

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